Easy Question - for someone

[ppgpilot]

Well, I've tried all my tricks but nothing works so far...

Problem:
I have a form that allows upload of 3 images. If only 1 image is uploaded - two empty - the script finishes img-1 and continues to the next image function to process img-2 and - of course - errors because there is no image-2.

Solution:
I need an IF statement (or somthing) to bypass the img-2 and img-3 functions (if empty), but the $_FILES['img-2'] is an array and the EMPTY, ISSET, and the "!" options do not work since the array always seems to return some value and I cannot set img-2 and img-3 to 0 for the db

Question:
How do you bypass an empty Array?

Code:
The first function works fine. The script stops at the second function due to invalid parameter passed to the function...

if(!isset($_FILES['img1']))
{
$img1 = 0;
}else{
$img= $_FILES['img1'];
$img1 = myimgupload($img);
}

if(!isset($_FILES['img2']))
{
$img2 = 0;
}else{
$img= $_FILES['img2'];
$img2 = myimgupload($img);
}
if(!isset($_FILES['img3']))
{
$img3 = 0;
}else{
$img= $_FILES['img3'];
$img3 = myimgupload($img);
}

Have not seen an example in my studies so far...
Thanks to the list in advance for your help!!

David

[Pheonix]

PHP: Select all

$n = 1;
foreach($_FILES as $img)
{
  $var = 'img'.$n;
  ${$var} = myimgupload($img);
  $n++;
} 

You will probaly need more security then this to prevent people from uploading 50 diffrent files etc. but this is basicly what you need.

[ppgpilot]

Thanks Pheonix!!

I tried your approach and it had the same results of failing if an image were not entered. (But I really like the small foot print in the script so I will use it for sure if I can figure out what I am doing wrong...

Maybe I am not using the form post correctly. I provide 3 boxes for the client to enter the 3 images. the code is listed below:

<b>Photo 1</b>
<input type="file" name="img1"><br />
<b>Photo 2</b>
<input type="file" name="img2"><br />
<b>Photo 3</b>
<input type="file" name="img3">

I POST everything from the form to the script so img1, img2, and img3 all go to the script - and all need to go to the file and db...

So the problem persists: I need a way for the script to bypass an array that is passed to the form...

Any thoughts


Thanks again!

David

[jdickinson]

If I understand your problem correctly:

When you submit a for with empty file fields the PHP script will pick these up as file arrays with empty data ( Try:

PHP: Select all

 print_r($_FILES); 

to see what's going on)

Therefore you need to put a check into your loop to test weather a file has been submitted. The following code (modified version of the above) should achieve this:

PHP: Select all

if($_FILES)
{
  $n = 1;
  
  foreach($_FILES as $img)
    if($img["name"]) #The test to see if a file is submitted
    {
      $var = 'img'.$n;
      ${$var} = myimgupload($img);
      $n++;
    }
}