insert works in firefox but not i.e.

[gecko]

I have a query to insert a product record into MySql database. Some products have flavours, some do not. On the form I have

PHP: Select all

if ($flav_exist !=  "y")  {
    $flavour = "";
} 

The insert query works fine in Firefox, but fails in Internet Explorer, without giving error message. Any ideas please.

[c010depunkk]

PHP runs on a server and is not dependent on the client browser....

PHP --> server side - generates HTML and sends it the the client browser.
HTML / Javascript --> client side.

[gecko]

I understand PHP runs on the server, but the query does not work. All I get is a blank screen.

[c010depunkk]

OK, maybe you could post a bit more code....

[ioncube]

Impossible to say without more code, however what you might do is verify that your HTML is not faulty. Any difference seen on the server side when submitting a form could be as a result of faulty form construction being interpreted differently by the client having a more or less forgiving parser, and resulting in data being posted differently. The result would be that your PHP script could behave differently if it wasn't getting some of the posted data. Similarly although less likely, after submitting the form you may have some page content returned but it's just not rendering.

Simple but effective debugging can be achieved by inserting some calls to var_dump() for any variables whose value affects program flow, as well as for $_POST or $_GET.

[Kropotkin]

Hi Gecko

If you are getting a blank screen from a PHP script that suggests a fatal error in the PHP script before it is ouptting any html.

There are a number of things which you can do:

Set PHP to output errors. You can set the display_errors to 1 in the php.ini and error_reporting to E_ALL. This will output all errors to the browser. The script may still fail but at least you will know why.

If you use shared hosting and cannot edit php.ini you can use ini_set in your script as in

Code: Select all

ini_set("display_errors", "1"); 
error_reporting(E_ALL);

This time hopefully you will see the error.

Justin

[gecko]

Thanks guys. I'm debugging script using "echo" and var_dump(), and displaying errors. Hopefully the error will show up soon.