incrementing variables with leading zeros

[saxman]

Not sure if this got posted last time I tried.

Here is the code in question;

*[code]*
<?
if ($picnumber == 001)
{
echo '<center><a href="index.html"><img src="buttons/home.gif" </a><a href="pic.php?picnumber='.++$picnumber.'"><img src="buttons/next.gif" </a></center>';
}
?>
*[code]*

The problem is that I need the incremented result for $picnum to equal "002" but it increments to "2".

Is there another way to increment or a way to initialize the variable so it retains the leading zeros and always keep a three digit number?

Thanks
Saxman

[spinal007]

use a string rather than a numerical datatype.
I don't do PHP but I hope you'll understand this pseudo:

Code: Select all

Function Digits(Number,HowMany)
 L = length of number
 s = number as a string
 While L<HowMany
  s = '0'.s
 Loop
 Return s

You can normally convert a number into a string by concatinating it with another string.
number = number & "" (in ASP)
$number = $number.'' (I think, in PHP)

Then, all you gotta do is:
[code]<?
if ($picnumber == 001)
{
echo '<center><a href="index.html"><img src="buttons/home.gif" </a><a href="pic.php?picnumber='.++Digits($picnumber,2).'"><img src="buttons/next.gif" </a></center>';
}
?>[code]

[Ryan Fait]

I believe if you put the "001" in quotes, it will read it as a string instead of as a number.

[spinal007]

Originally Posted by Ryan Fait

I believe if you put the "001" in quotes, it will read it as a string instead of as a number.

The thing is Ryan, he has a variable that is being incremented...
I think!

[grahame]

$val = sprintf("%03d",$val+1);

will take what's in $val, add 1 to it, format it to 3 digits leading 0 filled and put it back in $val.

[spinal007]

Originally Posted by grahame

$val = sprintf("%03d",$val+1);

will take what's in $val, add 1 to it, format it to 3 digits leading 0 filled and put it back in $val.

There you go, all you needed was a PHP expert...
LOL, I'll go back to the ASP section