[SOLVED] getting page file name.

hello, I have a file called lol.php - header.php is included into lol.php. header.php contains the script, and it needs to be here for asthetical reasons, and the function. I need to get the page name of lol.php from header.php. is this possible?

That was confusing and made little sense.
Post your code.

sorry, im very bad at explaining.

I have made an online example.

http://www.killerchutney.com/lol.php (aptly named ) heres the page I need to detect through header.php.

heres the code in header.php

Code: Select all

<div <?php
    function getpage() {
        $this_page = $_SERVER['PHP_SELF'];
         return $this_page;}
    
    if (getpage() == 'index.php'){
        echo ('id="content"');}
    
    elseif (getpage() == 'lol.php'){
        echo ('style="background-color:#ff00f6;"');}
        
    elseif (getpage() == '/templates/header.php'){
        echo ('style="background-color:#3cff00;"');}
    
    else{ echo ('style="background-color:#000000;"'); }?>>

if the script is working correctly, the background color of lol.php should be pink. If it is working incorrectly then it should be green (as it is now).

you can see in the left corner of the green div /templates/header.php - the include file name. but in the address bar it says http://www.killerch.../lol.php I need it to detect the URL shown in the address bar, instead the URL of the include.

Hmm, why do you want to detect a page? Can you describe your full goal. I have never come across a reason to detect another page unless there is some form or other data that needs to be validated...

WHy don't you create a global variable in the lol.php with the file name before you include the file?

The variable will hold the $_SERVER['php_self'] of lol.php and that way, because header.php gets all the variables declared when it is included, it has access to the calling file name.

ah! ok thank you this coupled with an answer from another forum it works perfectly now thank you once again.

No problems