[SOLVED] 2 weeks trying to update from a form

saltedm8 · #1 Oct 11th, 2007, 19:42

i have spent the last 2 weeks trying to update a table from a form and just cannot get it, the times i get no errors, it does not update, please help

change.php

PHP: Select all


<?php include 'config.php';?>
<?php include 'change_user.php';?>
<div align="center">
  <table width="355" border="1" bordercolor="#000000">
    <tr>
      <td height="439"><form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="post">
      <p>
        <div align="center">
    <p>&nbsp;</p>
    <p><strong>CREATE YOUR USERNAME AND PASSWORD</strong></p>
    <p>&nbsp;</p>
    <table width="408" height="79" border="1" bordercolor="#000000">
      <tr>
        <td width="197" height="38"><strong>ENTER NEW USERNAME</strong></td>
        <td width="201"><label>
          <div align="center">
            <input name="username" type="text" id="username" size="25" maxlength="25">
            </div>
        </label></td>
      </tr>
      <tr>
        <td><strong>ENTER NEW PASSWORD</strong></td>
        <td><label>
          <div align="center">
            <input name="password" type="text" id="password" size="25" maxlength="30">
            </div>
        </label></td>
      </tr>
    </table>
    <table width="413" border="0">
      <tr>
        <td width="407"><div align="right">
          <label>
          <input type="submit" name="Submit" id="Submit" value="Submit">
          </label>
        </div></td>
      </tr>
    </table>
    <p>&nbsp;</p>
  </div>
</form>&nbsp;
<table width="414" height="54" border="0">
  <tr>
    <td width="408">&nbsp;</td>
  </tr>
</table></td>
    </tr>
  </table>
</div>

change_user.php

PHP: Select all


<?php include 'config.php';?>
<?php
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql');
function filterThis($string) {
$string = htmlentities($string);
$string = mysql_real_escape_string($string);
return $string; }
$username = '$string';
$password = '$string' ;
$string = filterThis($username);
$string = filterThis($password);
$query = sprintf("SELECT * FROM members WHERE username AND password");
mysql_real_escape_string($username);
mysql_real_escape_string($password);
 
if (isset($_POST['submit'])) {
  $username = $_POST['username'];
  $password = $_POST['password'];
  $sql="UPDATE members id='username' 'password','
        VALUES ('$username','$password', )";
 
mysql_select_db("$dbname",$conn);
mysql_query($sql) or die (mysql_error());
}
?>

Rakuli · #2 Oct 12th, 2007, 07:14

Hi Saltedm8,

Can you explain a bit more about what you're trying to do? Do you have the current user details available anywhere or are these values to create a new entry in the database?

I have this code that is based off what little I could pick up from your script

PHP: Select all


<?php*include*'config.php';?>

<?php



// Connect to the database

$conn*=*mysql_connect($dbhost,*$dbuser,*$dbpass)*or*die*('Error*connecting*to*mysql');

mysql_select_db("$dbname",$conn) or die('Ooops, we have no db. I am sad now');

// Used to filter and return clean input

function*filterThis($string)*

{

$string*=*htmlentities($string);

$string*=*mysql_real_escape_string($string);

return*$string;*

}



// I'm not sure whether you are trying to retrieve data or add it so we'll do both

// $username*=*'$string'; What exactly is in $string?

// $password*=*'$string'*;





$username*=*filterThis($_POST['username']);

$password*=*filterThis($_POST['password']);

$query*=*"SELECT***FROM*members*WHERE*id = '$username'*AND*password = $password");

mysql_real_escape_string($username);

mysql_real_escape_string($password);

*

if*(isset($_POST['submit']))*{



    $username*=*filterThis($_POST['username']);

    $password*=*filterThis($_POST['password']);



    // to insert into use the INSERT SQL

**$sql="INSERT INTO*members*(id, password) 

********VALUES*('$username','$password',*)";*



mysql_query($sql)*or*die*(mysql_error());



    // To update you need to use the UPDATE Query but if you're changing both it would be good to have something

    // else to use in your WHERE clause like a user id or their current username so assuming you add a hidden form element

    // named currentid use this

    $currentid = filterThis($_POST['currentid']);

    $sql = "UPDATE members SET id = '$username', password = '$password' WHERE id = '$currentid'";

}

?>

AdRock · #3 Oct 12th, 2007, 09:03

As Rakuli has shown in the script that he came up with, that your SQL query was wrong and you didn't specify which record was getting updated.

Hese has a lot of useful examples on PHP, SQl etc so it worth having a look http://www.tizag.com/sqlTutorial/sqlupdate.php

saltedm8 · #4 Oct 12th, 2007, 16:53

i am just trying to create a form that is able to change an existing username and password stored in the database, but i wanted to use 'MD5()'

AdRock · #5 Oct 12th, 2007, 19:11

Who is doing the changing?

Is it the user who's username and password that need to be changed?

saltedm8 · #6 Oct 12th, 2007, 19:15

there only needs to be one table with id, username and password fields, only access will be for admin to do EVERYTHING, there will be no user access to anything on the site at all

i just want to be able to adjust it without entering the database, obviously converting it to md5 etc

AdRock · #7 Oct 12th, 2007, 20:04

How are you getting that record that needs to be updated? Are all usenames displayed in a table somewhere (html table) or are you going to search for a specific record?

i.e. I have a list of records with radio buttons and I click the radio button to edit that record

I only ask these questions becuase they are probably so many different ways to do it depending on the situation

saltedm8 · #8 Oct 12th, 2007, 20:31

mysql

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  $mem="CREATE TABLE members (
  id int(4) NOT NULL auto_increment,
        username varchar(65) NOT NULL default '',
        password varchar(65) NOT NULL default '',
        PRIMARY KEY (id)
      ) TYPE=MyISAM AUTO_INCREMENT=2 ";
 
  mysql_query($mem) or die (mysql_error());
 
  mysql_query("INSERT INTO `members` VALUES (1, 'saltedm8', md5('alarm7') )");

AdRock · #9 Oct 12th, 2007, 22:04

I've looked at your code and I should have a solution in my next post.

There seems to be a lot of confusion with you php and html and I will try and sort it out for you

AdRock · #10 Oct 12th, 2007, 22:30

A few things here

First, this only needs to be executed once

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$mem="CREATE TABLE members (
  id int(4) NOT NULL auto_increment,
        username varchar(65) NOT NULL default '',
        password varchar(65) NOT NULL default '',
        PRIMARY KEY (id)
      ) TYPE=MyISAM AUTO_INCREMENT=2 ";

2. You could just use this for username and same for password

PHP: Select all


$username - mysql_real_escape_string($_POST['username']);

3. Don't use tables for layout. I tried using your source code to see the form and it was all over the place and i didn't see any input fileds

4. Change these

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<input name="password" type="text" id="password" size="25" maxlength="30">

to

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<input name="password" type="password" name="password" size="25" maxlength="30">

HTML: Select all

<input name="username" type="text" id="username" size="25" maxlength="25">

to

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<input name="username" type="text" name="username" size="25" maxlength="25">

HTML: Select all

<input type="submit" name="Submit" id="Submit" value="Submit">

to

HTML: Select all

<input type="submit" name="Submit" name="Submit" value="Submit">

5. You could use this to create the md5 password

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$db_password = md5($password);

6. and to insert into the database use this

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mysql_query("INSERT INTO `members` (username, password) VALUES ('$username', '$db_password')");

7. When updating a record you need to know which record you are updating

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mysql_query("UPDATE users SET username='$username', password='$password WHERE id='$id'"))

When performing your SELECT query you could use the WHERE clause for either the id or username...it's up to you.

If you want to see an old example of mine before i improved it i'll post the code

saltedm8 · #11 Oct 13th, 2007, 14:09

what a bloomin pain that was !!!

ended with this

PHP: Select all


<?php include 'config.php';?>
<?php
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql');
if (isset($_POST['submit']))
{
$username = mysql_real_escape_string($_POST['username']); 
$db_password = mysql_real_escape_string($_POST['password']);
$db_password = md5($db_password);

$upmem ="INSERT INTO members (username, password) VALUES ($username, $db_password)"; 
$upmem = "UPDATE members SET username = '$username', password = '$db_password' WHERE 1"; 
mysql_select_db("$dbname",$conn);
mysql_query($upmem) or die (mysql_error());
}
?>

works perfectly

thanks for your help

AdRock · #12 Oct 13th, 2007, 14:28

You only need to perform one query for which action you want to take

When you add a new member you use

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$upmem ="INSERT INTO members (username, password) VALUES ($username, $db_password)";

When you want to update a member's details, you use

PHP: Select all


$upmem = "UPDATE members SET username = '$username', password = '$db_password' WHERE 1";

Just remember that your WHERE clause will always change depending on which record you want to update.

saltedm8 · #13 Oct 13th, 2007, 14:32

i was thinking about that, but i will sort that out later, at the moment i have built it for one user and no more, i could always re-write it later if i wanted - for now i am happy with what i have, cheers

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[SOLVED] 2 weeks trying to update from a form